72=18x^2

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Solution for 72=18x^2 equation:



72=18x^2
We move all terms to the left:
72-(18x^2)=0
a = -18; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-18)·72
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-18}=\frac{-72}{-36} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-18}=\frac{72}{-36} =-2 $

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